10x+2x^2=796

Solution for 10x+2x^2=796 equation:

10x+2x^2=796

We move all terms to the left:

10x+2x^2-(796)=0

a = 2; b = 10; c = -796;
Δ = b2-4ac
Δ = 102-4·2·(-796)
Δ = 6468
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{6468}=\sqrt{196*33}=\sqrt{196}*\sqrt{33}=14\sqrt{33}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-14\sqrt{33}}{2*2}=\frac{-10-14\sqrt{33}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+14\sqrt{33}}{2*2}=\frac{-10+14\sqrt{33}}{4}
$